Python 中的症状|子集.子集_索引()
原文:https://www.geesforgeks.org/sympy-subset-subset_indexs-in-python/
subset.subset_indexes():subset_indexes()是一个 sympy Python 库函数，返回列表中超集中子集的索引
语法: sympy.combinations.subset.subset.subset_indexs()
如果子集的所有元素都不在超集中，则返回: 列表中超集中子集的索引 。–列表为空
代码#1:子集_索引()示例
# Python code explaining
# SymPy.Subset.subset_indices()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.subset_indices()
# superset
super_set = [4, 3, 2, 7]
# Creating Subset
a = Subset.subset_indices((['geek', 'for', 'c', 'd']), super_set)
# subset_indices value
print ("Subset a subset_indices : ", a)
输出:
子集 a 子集_索引:[]
代码#2:子集_索引()示例
# Python code explaining
# SymPy.Subset.subset_indices()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.subset_indices()
# superset
super_set = [4, 3, 2, 7]
# Creating Subset
a = Subset.subset_indices(([2, 3, 4]), super_set)
# subset_indices value
print ("Subset a subset_indices : ", a)
输出:
子集 a 子集_索引:[2，1，0]
