Python 中的 SymPy | Subset.rank_词典学()
原文:https://www.geesforgeks.org/sympy-subset-rank_词典编纂-in-python/
subset.rank_dictionary():rank_dictionary()是一个 sympy Python 库函数，返回子集的字典排序。
语法: sympy.combinations.subset.subset.rank_dictionary graphic()
返回: 该子集的词典排名。
代码# 1:rank_dictionary()示例
# Python code explaining
# SymPy.Subset.rank_lexicographic()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.rank_lexicographic()
# Creating Subset
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd'])
# rank_lexicographic value
print ("Subset a rank_lexicographic : ", a.rank_lexicographic)
输出:
子集 a 等级_字典顺序:14
代码# 2:rank_dictionary()示例
# Python code explaining
# SymPy.Subset.rank_lexicographic()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.rank_lexicographic()
# Creating Subset
a = Subset([2, 3, 4], [1, 2, 3, 4, 5])
# rank_lexicographic value
print ("Subset a rank_lexicographic : ", a.rank_lexicographic)
输出:
子集 a 等级_字典顺序:19
