Python 中的 SymPy | arrangement.next_trotterjohnson()
原文:https://www.geeksforgeeks.orgpy-置换-next_trotterjohnson-in-python/
arrangement.next_trotterjohnson():next_trotterjohnson()是一个 sympy Python 库函数，返回 Trotter-Johnson 顺序的下一个排列。如果 self 是最后一个置换，则返回 None。
语法:sympy.combinations.arranges.arrangement.next_trotterjohnson()
返回:特罗特-约翰逊顺序的下一个排列
代码#1 : next_trotterjohnson()示例
# Python code explaining
# SymPy.Permutation.next_trotterjohnson()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson())
print ("Permutation b - next_trotterjohnson form : ", b.next_trotterjohnson())
输出:
排列 a–next_trotterjohnson 形式:(0 3 1 2) 排列 b–next_trotterjohnson 形式:(0 1 5)(2 3 4)
代码#2 : next_trotterjohnson()示例–2D 置换
# Python code explaining
# SymPy.Permutation.next_trotterjohnson()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.next_trotterjohnson() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - next_trotterjohnson form : ", a.next_trotterjohnson())
输出:
排列 a–next_trotterjohnson 形式:(6)(0 3 5 1 2 4)
