Python 中的 SymPy | arrangement.next_nonlex()
原文:https://www.geesforgeks.org/sympy-置换-next_nonlex-in-python/
arrangement.next_nonlex():next_nonlex()是一个 sympy Python 库函数，它以非词典顺序返回下一个排列，如果 self 是非词典顺序的最后一个排列，则返回 None。
语法:sympy.combinations .排列.置换. next_nonlex()
返回:非词典顺序的下一个排列
代码#1 : next_nonlex()示例
# Python code explaining
# SymPy.Permutation.next_nonlex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.next_nonlex() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
print ("Permutation a - next_nonlex form : ", a.next_nonlex())
print ("Permutation b - next_nonlex form : ", b.next_nonlex())
输出:
排列 a–next_non lex 形式:(0 3 2) 排列 b–next_non lex 形式:(0 5 1 3 4 2)
代码#2 : next_nonlex()示例–2D 置换
# Python code explaining
# SymPy.Permutation.next_nonlex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.next_nonlex() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - next_nonlex form : ", a.next_nonlex())
输出:
排列 a–next_nonlex 形式:(0 3 5 1 6 2 4)
