Python 中的 SymPy | arrangement.next_lex()
arrangement.next_lex():next_lex()是一个 sympy Python 库函数，它返回字典顺序中的下一个排列，如果 self 是字典顺序中的最后一个排列，则返回 None。
语法:sympy.combinations .排列.置换. next_lex()
返回:字典顺序中的下一个排列
代码#1 : next_lex()示例
# Python code explaining
# SymPy.Permutation.next_lex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.next_lex() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
print ("Permutation a - next_lex form : ", a.next_lex())
print ("Permutation b - next_lex form : ", b.next_lex())
输出:
排列 a–next_lex 形式:(0 2 1 3) 排列 b–next_lex 形式:(5)(0 1 4 3 2)
代码#2 : next_lex()示例–2D 置换
# Python code explaining
# SymPy.Permutation.next_lex()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.next_lex() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - next_lex form : ", a.next_lex())
输出:
排列 a–next_lex 形式:(6)(0 3 5)(1 2 4)
