Python 中的 SymPy | arrangement.is_Identity()
原文:https://www.geesforgeks.org/sympy-arrange-is_identity-in-python/
arrangement.is_Identity():is_Identity()是一个 sympy Python 库函数，用于检查 arrange 是否是一个身份置换。
语法:sympy.combinations .排列.置换. is_Identity()
返回:true–如果他置换是一个身份置换；否则为假
代码#1 : is_Identity()示例
# Python code explaining
# SymPy.Permutation.is_Identity()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
print ("Permutation a - is_Identity form : ", a.is_Identity)
print ("Permutation b - is_Identity form : ", b.is_Identity)
输出:
排列 a–is_Identity 形式:假 排列 b–is_Identity 形式:假
代码#2 : is_Identity()示例–2D 置换
# Python code explaining
# SymPy.Permutation.is_Identity()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - is_Identity form : ", a.is_Identity)
输出:
排列 a–is_Identity 形式:假
