Python–Sympy 多边形. distance()方法
原文:https://www.geesforgeks.org/python-sympy-polygon-distance-method/
在 Sympy 中，函数 Polygon.distance() 用来返回给定多边形与 o 之间的最短距离，如果 o 是一个点，那么给定多边形不需要是凸的。但是如果 o 是另一个多边形，那么给定的多边形和 o 一定是凸的。
Syntax: Polygon.distance(o)
Parameters:
o:Point or Polygon
Returns: the shortest distance between the given polygon and o.
示例#1:
蟒蛇 3
# import sympy import Point, Polygon
from sympy import Point, Polygon
# creating points using Point()
p1, p2, p3, p4 = map(Point, [(0, 2), (0, 0), (1, 0), (1, 2)])
# creating polygon using Polygon()
poly = Polygon(p1, p2, p3, p4)
# using distance()
shortestDistance = poly.distance(Point(3, 5))
print(shortestDistance)
输出:
sqrt(13)
例 2:
蟒蛇 3
# import sympy import Point, Polygon, RegularPolygon
from sympy import Point, Polygon, RegularPolygon
# creating points using Point()
p1, p2 = map(Point, [(0, 0), (7, 5)])
# creating polygon using Polygon() and RegularPolygon()
poly = Polygon(*RegularPolygon(p1, 1, 3).vertices)
# using distance()
shortestDistance = poly.distance(p2)
print(shortestDistance)
输出:
sqrt(61)
