Python | SymPy 置换. cycles()方法

原文:https://www.geesforgeks.org/python-sympy-置换-循环-方法/

置换. cycles() : cycles() 是一个 sympy Python 库函数，返回置换中存在的循环数。这也包括单例。

语法: 组合学.排列.置换.循环()

返回: 排列中出现的循环数

代码#1:周期()示例

# Python code explaining
# SymPy.Permutation.cycles()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from sympy.combinatorics.permutations.Permutation.cycles() method 

# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])

b = Permutation([3, 1, 2, 5, 4, 0])

print ("Permutation a - cycles form : ", a.cycles)
print ("Permutation b - cycles form : ", b.cycles)

输出:

置换 a–循环形式:2 置换 b–循环形式:4

代码#2:循环()示例–2D 置换

# Python code explaining
# SymPy.Permutation.cycles()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from 
# sympy.combinatorics.permutations.Permutation.cycles() method 

# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])

# SELF COMMUTATING    
print ("Permutation a - cycles form : ", a.cycles)

输出:

置换 a–循环形式:1

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