Python | SymPy placement.cycle_structure()方法
原文:https://www.geesforgeks.org/python-sympy-置换-cycle_structure-method/
replacement.cycle_structure():cycle_structure()是一个 sympy Python 库函数，它将置换的循环结构作为字典返回，这将指示每个循环长度的多重性。
语法: sympy.combinations .排列.置换. cycle_structure()
返回: 循环结构的排列作为字典
代码#1 : cycle_structure()示例
# Python code explaining
# SymPy.Permutation.cycle_structure()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.cycle_structure() method
# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])
b = Permutation([3, 1, 2, 5, 4, 0])
print ("Permutation a - cycle_structure form : ", a.cycle_structure)
print ("Permutation b - cycle_structure form : ", b.cycle_structure)
输出:
置换 a–cycle_structure 形式:{2: 1，4: 1} 置换 b–cycle_structure 形式:{1: 3，3: 1}
代码#2 : cycle_structure()示例–2D 置换
# Python code explaining
# SymPy.Permutation.cycle_structure()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.cycle_structure() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
# SELF COMMUTATING
print ("Permutation a - cycle_structure form : ", a.cycle_structure)
输出:
排列 a–cycle_structure 形式:{7: 1}
