Python | SymPy placement .通勤 _with()方法
原文:https://www.geesforgeks.org/python-sympy-置换-通勤 _with-method/
replacement .通勤 _with():通勤 _with() 是一个 sympy Python 库函数，检查两个置换是否在通勤。假设‘a’和‘b’是‘C’的一部分，那么 a 和 b 的换向器就是‘C’的同一性if a 和 b 的通勤，即 ab == ba。
语法: sympy.combinations.arranges.replacement .通勤 _with()
返回: 检查两个排列是否在交换
代码#1:用()通勤_示例
# Python code explaining
# SymPy.Permutation.commutes_with()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.commutes_with() method
# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])
b = Permutation([3, 1, 2, 5, 4, 0])
print ("Permutation a - commutes_with form : ", a.commutes_with(b))
print ("Permutation b - commutes_with form : ", b.commutes_with(a))
输出:
排列 a–以形式通勤_假 排列 b–以形式通勤_假
代码#2:用()通勤_示例–自换向器
# Python code explaining
# SymPy.Permutation.commutes_with()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.commutes_with() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
# SELF COMMUTATING
print ("Permutation a - commutes_with form : ", a.commutes_with(a))
输出:
置换 a–用形式通勤_真
