Python | Sympy line.vertical_segment()方法
原文:https://www.geesforgeks.org/python-sympy-line-vertical_segment-method/
In Sympy, the function perpendicular_segment() is used to create a perpendicular line segment from a given point to the given line.The endpoints of the segment are p and theclosest point in the line containing self.
Syntax: Line.perpendicular_segment(p)
Parameters:
p: Point
Returns:
segment: Segment
示例#1:
# import sympy and Point, Line
from sympy import Point, Line
p1, p2, p3 = Point(0, 0), Point(1, 1), Point(0, 2)
l1 = Line(p1, p2)
# using perpendicular_segment() method
perpendicularSegment = l1.perpendicular_segment(p3)
print(perpendicularSegment)
输出:
Segment2D(Point2D(0, 2), Point2D(1, 1))
示例#2:
# import sympy and Point3D, Line3D
from sympy import Point3D, Line3D
p1, p2, p3 = Point3D(0, 0, 0), Point3D(1, 1, 1), Point3D(0, 2, 0)
ll1 = Line3D(p1, p2)
# using perpendicular_segment() method
s1 = l1.perpendicular_segment(p3)
perpendicularSegment = l1.perpendicular_segment(p3)
print(perpendicularSegment)
输出:
Segment3D(Point3D(0, 2, 0), Point3D(2/3, 2/3, 2/3))
