Python | sympy.bernoulli()方法
原文:https://www.geesforgeks.org/python-sympy-Bernoulli-method/
借助辛.伯努利()方法，我们可以在辛中找到伯努利数和伯努利多项式。
bernoulli(n) -
语法:伯努利(n)
参数: n–表示第 n 个伯努利数。
返回:返回第 n 个伯努利数。
示例#1:
# import sympy
from sympy import * n = 4
print("Value of n = {}".format(n))
# Use sympy.bernoulli() method
nth_bernoulli = bernoulli(n)
print("Value of nth bernoulli number : {}".format(nth_bernoulli))
输出:
Value of n = 4
Value of nth bernoulli number : -1/30
bernoulli(n, k) -
语法:伯努利(n，k)
参数: n–它表示伯努利多项式的阶。 k–表示伯努利多项式中的变量。
返回:返回伯努利多项式的表达式或其值。
例 2:
# import sympy
from sympy import * n = 5
k = symbols('x')
print("Value of n = {} and k = {}".format(n, k))
# Use sympy.bernoulli() method
nth_bernoulli_poly = bernoulli(n, k)
print("The nth bernoulli polynomial : {}".format(nth_bernoulli_poly))
输出:
Value of n = 5 and k = x
The nth bernoulli polynomial : x**5 - 5*x**4/2 + 5*x**3/3 - x/6
示例#3:
# import sympy
from sympy import * n = 4
k = 3
print("Value of n = {} and k = {}".format(n, k))
# Use sympy.bernoulli() method
nth_bernoulli_poly = bernoulli(n, k)
print("The nth bernoulli polynomial value : {}".format(nth_bell_poly))
输出:
Value of n = 4 and k = 3
The nth bernoulli polynomial value : 10*x1**2*x3 + 15*x1*x2**2
